**Definition:** The internal bisector of angle A and external bisectors of angles B, C of ΔABC are concurrent. The point of concurrence is called ex-centre of ΔABC opposite to the vertex A. It is denoted by I₁. The point I₁ is equidistant to the sides of the triangle. The circle with centre I₁ and touching the three sides of the triangle is called excircle of triangle ABC opposite to the vertex A. The radius of this ex-circle is called ex-radius of triangle ABC and it is denoted by r₁. The excentres of ΔABC opposite to the vertices B, C are respectively denoted by I₂, I₃. The ex-radii of triangle ABC opposite to the vertices B, C are respectively denoted by r₂, r₃.

**Statement:** In ΔABC, \({{r}_{1}}=\frac{\Delta }{s-a}\).

**Proof:** Let I₁ be the excentre of ΔABC opposite to the vertex A.

Let X, Y, Z be the projections of I₁ on BC, CA, AB. ∴ I₁X = I₁Y = I₁Z = r₁

Δ = Area of ΔABC

= Area of Δ AI₁B + Area of ΔAI₁C – Area of ΔBI₁C

= ½ AB.I₁X + ½AC.I₁Y – ½BC.I₁Z = ½c r₁ + ½b r₁ – ½a r₁

= ½r₁ (c + b – a) = ½r₁ 2(s – a) = r₁ (s – a) → r₁ = Δ / s – a.

Similarly, r₂ = Δ / s – b, r₃ = Δ / s – c.

**Statement:** In ΔABC, r₁ = 4R sinA/2 cos B/2 cos C/2.

**Proof: **4R sin A/2 cos B/2 cos C/2\(=4R\sqrt{\frac{(s-b)(s-c)}{bc}}\sqrt{\frac{s(s-b)}{ca}}\sqrt{\frac{s(s-c)}{ab}}\),

\(=\frac{4Rs\left( s-b \right)\left( s-c \right)}{abc}=\frac{4Rs\left( s-a \right)\left( s-b \right)\left( s-c \right)}{\left( s-a \right)4R\Delta }=\frac{{{\Delta }^{2}}}{\left( s-a \right)\Delta }=\frac{\Delta }{s-a}={{r}_{1}}\).

**Statement: **In \(\Delta ABC,\,{{r}_{1}}=s\tan \frac{A}{2}=\left( s-b \right)\cot \frac{C}{2}=\left( s-c \right)\cot \frac{B}{2}\).

**Proof: **\(\Delta ABC,\,{{r}_{1}}=s\tan \frac{A}{2}=\left( s-b \right)\cot \frac{C}{2}=\left( s-c \right)\cot \frac{B}{2}\)

\(\left( s-b \right)\cot \frac{C}{2}=\left( s-b \right)\sqrt{\frac{s\left( s-c \right)}{\left( s-a \right)\left( s-b \right)}}=\frac{\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}}{s-a}=\frac{\Delta }{s-a}={{r}_{1}}\)

Similarly, \(\left( s-c \right)\cot \frac{B}{2}={{r}_{1}}\).

**Statement:** In\(\Delta ABC,\,{{r}_{1}}=\frac{a}{\tan \left( B/2 \right)+\tan \left( C/2 \right)}\).

**Proof:** \({{r}_{1}}\left( \tan \frac{B}{2}+\tan \frac{C}{2} \right)=\frac{\Delta }{s-a}\left[ \sqrt{\frac{\left( s-c \right)\left( s-a \right)}{s\left( s-b \right)}}+\sqrt{\frac{\left( s-a \right)\left( s-b \right)}{s\left( s-c \right)}} \right]\)

\(=\frac{\Delta }{s-a}\left[ \frac{\left( s-c \right)\sqrt{s-a}+\left( s-b \right)\sqrt{s-a}}{\sqrt{s\left( s-b \right)\left( s-c \right)}} \right]=\frac{\Delta \sqrt{s-a}\left( s-c+s-b \right)}{\left( s-a \right)\sqrt{s\left( s-b \right)\left( s-c \right)}}\)

\(=\frac{\Delta \left( a+b+c-c-b \right)}{\sqrt{s\left( s-a \right)\left( s-b \right)\left( s-c \right)}}=\frac{\Delta a}{\Delta }=a\)

∴ \({{r}_{1}}=\frac{a}{\tan \left( B/2 \right)+\tan \left( C/2 \right)}\).

**Statement:** In ΔABC,

i) \(\frac{1}{{{r}_{1}}}+\frac{1}{{{r}_{2}}}+\frac{1}{{{r}_{3}}}=\frac{1}{r}\)

ii) rr₁r₂r₃ = Δ²

**Proof:**

i) \(\frac{1}{{{r}_{1}}}+\frac{1}{{{r}_{2}}}+\frac{1}{{{r}_{3}}}=\frac{s-a}{\Delta }+\frac{s-b}{\Delta }+\frac{s-c}{\Delta }=\frac{s-a+s-b+s-c}{\Delta }\)

\(=\frac{3s-\left( a+b+c \right)}{\Delta }=\frac{3s-2s}{\Delta }=\frac{s}{\Delta }=\frac{1}{r}\).

ii) \(r{{r}_{1}}{{r}_{2}}{{r}_{3}}=\frac{\Delta }{s}.\frac{\Delta }{s-a}\frac{\Delta }{s-b}\,.\,\frac{\Delta }{s-c}=\frac{{{\Delta }^{4}}}{{{\Delta }^{2}}}={{\Delta }^{2}}\).

]]>The most important application of Newton’s motion Laws is the explanation of tension. Ropes and strings are very useful in machines and mechanical systems. These are used to push or pull heavy loads. We can see the tension in using of ropes or cables. If we consider a load which is pulled by a rope, a person is exerting a force at one end of the rope who is not directly in the contact of the block. Thus, the force which is felt by block through the use of rope is called tension force.

**What is Tension?**

When a string or rope is tugged on the force that is applied on it when it is tugged on is termed as tension. The tension force is felt be every section of the rope in both the directions, apart from the end points. The end points experience tension on one side and the force from the weight attached. Throughout the string the tension varies in some circumstances.

“Tension is a pulling force applied by a string or chain on another body”.

**Assumptions:**

- The rope strings and cables have no mass.
- The tension remains same throughout the rope.

**Tension Formula:**

Tension \(\)\left( T \right)\,\,=\,\,\left( \frac{2{{m}_{1}}{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}} \right)g\].

**Law of Tension: **The frequency of transverse vibration of a strained string is proportional to the square root of the tension (T) exerted on the string provided the vibrating length l and mass per unit length mm are kept constant.

v α √T, if l and m are constant.

**How to find the Tension?**

**Problem: **There are two books of mass 5kg and 2kg is tied to the two end of the string. Find the tension in the string if the system is free?

**Solution: **Given,

Mass (m₁) = 5 kg

Mass (m₂) = 2 kg

Acceleration due to gravity (g) = 9.8 m/ sec²

Tension (T) =?

We know that:

Tension \(\)\left( T \right)\,\,=\,\,\left( \frac{2{{m}_{1}}{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}} \right)g\],

\(\)T\,\,=\,\,\left( \frac{2\times 5\times 2}{5+2} \right)\times 9.8\,\,=\,\,28N\],

Therefore, the tension in the spring is 28N.

]]>Admission into AYUSH (BHMS) course under Management Quota seats in Private Un-aided Non-Minority Homeo Colleges in the State of Telangana for the year 2018-19

**Important Dates:**

1 |
Date of issue of Notification to apply for admission to AYUSH(BHMS) Course for the academic year 2017-18 | 15.09.2018 |

2 | Availability of online Application form website https://tsbhmsmq.tsche.in |
From 9.00AM on 18.09.2018 upto 5.00PM on 27.09.2018 |

3 |
Date of release of provisional merit position of all the candidates applied for |
28.09.2018 |

4 | Dates of verification of original Certificates and Counselling at Prof. Ramreddy centre for distance education, O.U. Campus, Hyderabad. (PGRRCDE) |
To be notified |

5 |
Commencement of Classes | To be notified |

6 | Closure of Admissions |
To be notified |

**Note:** All the above dates are tentative and the University reserves the right to change them without assigning any reason or advance notice.

**Eligibility:**

i) Candidates from all over the country are eligible for admission into Management quota seats (Category -B and C) for UG AYUSH(BHMS) Course and as per CCIM/ CCH/ KNR University of Health Sciences.

ii) The candidate should have passed Intermediate (10+2 pattern) or its equivalent examination with Physics, Chemistry, Biology (Botany, Zoology)/ Biotechnology and English.

- OC candidates should obtain not less than 50% marks in science subjects.
- BC/ SC/ ST candidates should obtain not less than 40% marks in science subjects.
- OC PH candidates should obtain not less than 45% marks in science subjects.

iii) Candidates should have qualified at NEET UG – 2018

iv) The candidates should secure the following cut-off scores in NEET UG-2018 conducted by CBSE, New Delhi for the year 2018-19.

Category |
Qualifying criteria | Cut off score (out of 720) |
Remarks |

General category |
50% percentile | 119 |
Candidates scoring equal or more than this cut off score have been declared as qualified |

SC/ ST/ BC |
40% percentile | 96 | ST/ SC/ BC Candidates scoring equal or more than this cut off score have been declared as qualified |

Persons with disability | 45% percentile | 107 |
OC – PH Candidates scoring equal or more than this cut off score have been declared as qualified |

v) Lower percentage/ percentile of marks for SC/ ST/ BC/ PH is only for eligibility purpose and will not be applicable for reservation as there are no reservation quotas for these categories.

viii) Foreign Students/ NRI candidates are eligible for admission into AYUSH Courses under Management Quota Category – C Seats.

ix) Candidates who have already applied for Convener Quota Seats in response to this University earlier notification are also eligible for the management quota seats, but they have to apply afresh.

x) Candidates possessing qualification of the University/ Board of an institution outside the Telangana State should submit Eligibility/ Equivalence certificate from the Board of Intermediate Education of Telangana, to the effect that the qualification possessed is equivalent to or higher than Intermediate examination conducted by the Board of Intermediate Education of Telangana at the time of admission into the college.

xi) Candidates possessing qualification of the University/ Board of an institution outside INDIA should submit Eligibility/ Equivalence certificate issued by Association of Indian Universities, New Delhi and Eligibility/ Equivalence certificate issued from the Board of Intermediate Education of Telangana to the effect that the qualification possessed is equivalent to or higher than Intermediate examination conducted by the Board of Intermediate Education of Telangana at the time of admission into the college.

xii) The probable number of seats under management quota is given in the Annexure appended herewith, for information.

**Age:** The candidate should have completed 17 years of age as on 31-12-2018. The candidates who do not complete 17 years as on 31-12-2018 need not attend the counseling.

The candidates born on or after 02-01-2002 are not eligible for admission into BHMS Course.

**Penal action:**

i. If the candidate withdraws from the course after Closure of Admission of Management Quota Seats to a College, he/ she will forfeit the tuition fee paid for that academic year and has to pay the tuition fee for the rest of the course, along with discontinuation fee of Rs. 1-Lakh to University as mentioned in G.O.170 HM&FW(E1) Dept. Dated:19-9-2017.

ii. The candidate selected in the final counseling, will not be permitted to cancel the selection. All the selected candidates shall submit an undertaking that he / she will pay the tuition fee for the entire course along with discontinuation fee of Rs. 1- Lakhs to University as mentioned in G.O.170 HM&FW(E1) Dept. Dated:19-9-2017. to avoid wastage of seats, in case withdraws from the college after admission.

iii. The Original Certificates submitted by the candidates or who withdraws from the Course, before issue of notification for final round of counseling, will be returned.

**Fee Structure:**

** University Fee:** The selected candidates shall pay non – refundable University fee in the form of crossed Demand Draft drawn in favour of “The Registrar, KNR University of Health Sciences” payable at Warangal, as given below.

Category |
AYUSH Course |

B – Category |
15,000=00 |

C-Category |
20,000=00 |

** Tuition fee:** As fixed by the Government of Telangana.

**Note – 1:** The candidates selected against Management Quota Category-B & C Seats shall pay the tuition fee fixed for management Quota seat on the day of reporting in the form of Demand Draft in the name of the Principal of the respective college on the day of admission to the college. If the candidate fails to pay the tuition fee within the time of joining, the admission will be cancelled automatically.

**Registration and Processing Fee:** Rs. 4000/- (Bank transaction charges extra).

**Note:** Candidates are informed that they have to attend for counseling with DD towards university fee on the day of selection/ counselling and submit the DD to obtain allotment letter. If the candidate fails to submit the DD for university fee after choosing the seat, the seat will be cancelled automatically without any notice. The candidates will not be given any extension of time to pay the fee. Candidates have to pay the tuition fee at the time of admission at respective colleges. If the candidate fails to pay the tuition fee at the concerned college within stipulated time the admission will be cancelled automatically.

The selected candidates shall submit bank guarantee for remaining period of study

]]>All the candidates who have applied online under PH quota are informed to attend the counselling.

**Date of Counseling:** 25-09-2018

**Time:** 10.00 AM

**Venue:** University Auditorium, P.J.T.S.A.U., Rajendranagar.

Sl. No |
Name of the Course |
No. of Seats under PH Quota |

1 |
B.V.Sc. & A.H. | 04 Seat |

2 | B.Sc. (Hons.) Agriculture |
13 Seat |

3 | B.Sc. (Hons.) Horticulture |
04 Seat |

4 |
B.Sc. (Hons.) Horticulture (Payment) | 01 Seat |

5 | B.F.Sc. |
01 Seat |

Candidates with following disabilities will not be admitted as per VCI norms for admission into B. V. Sc. & A. H. course.

- Disability of total body including disability of chest or spine more than 50%.
- Disability of lower limb of more than 50%.
- Disability of upper limb.
- Visually Handicapped Candidates and those with hearing disability.
- Candidates with progressive diseases like myopathies etc.,
- Disabilities which otherwise would interfere in the performance of the duties of a veterinarian.

**Screening tests as per the requirement of the courses concerned shall be conducted to evaluate the suitability of the candidates to pursue the courses for admission into various UG courses.**

**I. Visually Handicapped (PJTSAU & SKLTSHU)**

- Reading the information on blackboard/ whiteboard from a distance of 15 feets.
- Writing a small paragraph.
- Identification of slides through microscope.
- Field Operation (Eg Weeding/ Spraying).
- Needle work.

**II. Hearing Impaired (PJTSAU & SKLTSHU)**

- Listening and writing the word/sentence.
- Listening and doing the practical work.
- Listening and writing the answers to the questions.
- Listening and answering the questions.
- Listening and doing the assigned work (For all these tests the assigned work will be recorded in tape recorder and played from a fixed distance with a fixed volume).

**III. Orthopedically Handicapped (PJTSAU, PVNRTVU & SKLTSHU)**

- Field operations.
- Manually operated wheel push hoes.
- Walking.
- Writing.
- Weeding/Spraying.

**⇒ **More number of candidates than required are called for counseling and therefore this call does not guarantee admission into courses to all those who have been called for.

**⇒ **The selected candidates will have to pay the requisite fees including deposits immediately (Rs. 33,050/- for B.Sc. (Hons.) Agriculture per semester in PJTSAU, for B.V.Sc. & A.H. Rs. 43,215/- per annum, for B.F.Sc. Rs. 32,845/-per semester (PVNRTVU), Rs. 32,700/- for B.Sc. (Hons.) Horticulture and Rs. 68,700/- for B.Sc. (Hons.) Horticulture (Payment) per semester in SKLTSHU) failing which the seat will stand cancelled.

**⇒ **Based on the priority’s seats shall be filled up as per ranks obtained in the Telangana EAMCET-2018 and rule of reservation.

**⇒ **Candidates are informed to read the prospectus (Information Brochure) thoroughly before attend the counselling.

**⇒ **The Candidates are informed to attend the counseling one hour before the scheduled time.

**Statement:** Tan⁻¹ x + Tan⁻¹ y = Tan⁻¹ \(\left( \frac{x+y}{1-xy} \right)\) for x > 0, y > 0, xy < 1 = π + Tan⁻¹ \(\left( \frac{x+y}{1-xy} \right)\) for x > 0, y > 0, xy > 1.

**Proof:**

**Case (i):** Suppose x > 0, y > 0, xy < 1

x > 0 → 0 < Tan⁻¹ x < π/2

y > 0 → 0 < Tan⁻¹ y < π/2

Let Tan⁻¹ x = α, Tan⁻¹ y = β

Then x = Tan α, y = Tan β

0 < Tan⁻¹ x < π/2 → 0 < α < π/2

0 < Tan⁻¹ y < π/2 → 0 < β < π/2

0 < α < π/2, 0 < β < π/2 → 0 < α + β < π

\(\tan \left( \alpha +\beta \right)=\frac{\tan \alpha +\tan \beta }{1-\tan \alpha \tan \beta }=\frac{\operatorname{Tan}\alpha +\operatorname{Tan}\beta }{1-\operatorname{Tan}\alpha \operatorname{Tan}\beta }=\frac{x+y}{1-xy}>0\).

0 < α + β < π, tan (α + β) > 0

0 < α + β < π / 2

∴ Tan (α + β) = tan (α + β)

= \(\frac{x+y}{1-xy}\Rightarrow {{\operatorname{Tan}}^{-1}}\frac{x+y}{1-xy}\).

= α + β = Tan⁻¹ x + Tan⁻¹ y

**Case (ii): **Suppose x > 0, y > 0, xy > 1

x > 0 → 0 < Tan⁻¹ x < π/2

y > 0 → 0 < Tan⁻¹ y < π/2

Let Tan⁻¹ x = α, Tan⁻¹ y = β.

Then x = Tan α, y = Tan β

0 < Tan⁻¹ x < π / 2, 0 < Tan⁻¹ y < π/2

0 < α < π/2, 0 < β < π/2

0 < α + β < π

\(\tan \left( \alpha +\beta \right)=\frac{\tan \alpha +\tan \beta }{1-\tan \alpha \tan \beta }=\frac{\operatorname{Tan}\alpha +\operatorname{Tan}\beta }{1-\operatorname{Tan}\alpha \operatorname{Tan}\beta }=\frac{x+y}{1-xy}<0\).

0 < α + β < π, tan (α + β – π)

= -tan [π – (α + β)]

= tan (α + β) \(=\frac{x+y}{1-xy}\).

Tan⁻¹\(\frac{x+y}{1-xy}\) = α + β – π

α + β = π + Tan⁻¹\(\frac{x+y}{1-xy}\).

Tan⁻¹ x + Tan⁻¹ y = π + Tan⁻¹\(\frac{x+y}{1-xy}\).

]]>The degrees of freedom can be calculated to help ensure the statistical validity of t – tests and even the more advanced f – tests. The number of degrees of freedom refers to the difference between the numbers of independent observations in a sample and the number of population parameters that must be estimated from sample data.

**What is Degrees of Freedom?**

The number of degrees of freedom of a dynamical system is defined as the total number of co – ordinates or independent variables required to describe the position and configuration of the system. If a particle is moving a straight line along any one of the axis, it has one degree of freedom. If a particle is moving in a plane, it has two degrees of freedom. If a particle is moving in space, it has three degrees of freedom.

A point mass cannot undergo rotation, but only translatory motion. A rigid body with finite mass has both rotatory and translatory motion. The rotatory motion also can have three co-ordinates in space, like translatory motion. Therefore, a rigid body will have six degrees of freedom. Three dues to translatory motion and three dues to rotatory motion.

**Monoatomic Molecule: **Since a monoatomic molecule consists of only a single atom of point mass it has three degrees of freedom of translatory motion along the three co-ordinate axes as shown in the below figure.

**Example:** Molecules of rare gases like helium, argon, etc.

**Diatomic Molecule: **The diatomic molecule can rotate about any axis at right angles to its own axis. Hence it has two degrees of freedom of rotational motion in addition to three degrees of freedom of translational motion along the three axes. So, a diatomic molecule has five degrees of freedom as shown in the below figure.

**Examples:** Molecules of N₂, CO, Cl₂, etc.

**Triatomic Molecule: **In the case of triatomic molecule of linear type, the centre of mass lies at the central atom. It, therefore, behaves like a diatomic molecule with three degrees of freedom of translation and two degrees of freedom of rotation, totally it has five degrees of freedom as shown in below figure.

**Examples:** Molecules of CO₂, CS₂, etc.

Angular speed is the rate at which an object changes its angle in radians, in a given time period. Angular speed has a magnitude only.

\(Angular\,\,Speed\,\,=\,\,\frac{\left( Final\,\,Angle\,\,-\,\,Initial\,\,Angle \right)}{time}\,\,=\,\,\frac{Change\,\,in\,\,position}{time}\)

Angular Speed (ω) = θ/ t

Where,

ω = Angular Speed in rad/sec,

θ = Angle in radians,

t = time in seconds.

Angular speed and angular velocity uses the same formula. The difference between the two is that Angular speed is a scalar quantity, while angular velocity is a vector quantity.

**How to find the Angular Speed?**

**Problem: **At the state fair, you take your younger sister to ride the Ferris wheel. You notice that a sign says that the angular speed of the Ferris wheel is 0.13 rad/sec. How many revolutions will the wheel complete in 12 minutes?

**Solution: **Given,

Angular speed (ω) = 0.13 rad/ sec

Time (t) = 12 min = 720 sec

We know that:

Angular Speed (ω) = θ/ t

θ = ω x t = (0.13 rad/ sec) x 720 sec = 93.6 rad.

θ = 93.6/ 2π revolutions = 14.9 ≈ 15 revolutions.

∴ θ = 15 revolutions.

]]>**Statement:** √a + ib = ± (x + iy) where \(x=\sqrt{\left( \frac{\sqrt{{{a}^{2}}+{{b}^{2}}}+a}{2} \right)},\,y=\sqrt{\left( \frac{\sqrt{{{a}^{2}}+{{b}^{2}}}-a}{2} \right)}\).

**Proof:** √a + ib = ± (x + iy) → a + ib = (x + iy)² = x² – y² + 2ixy

a = x² – y² … (1)

b = 2xy … (2)

∴ (x² + y²)² = (x² – y²)² + 4x² y² = a² + b² → x² + y² = √a² + b² … (3)

Adding (1) and (3), 2x² = √a² + b² + a → \(x=\sqrt{\left( \frac{\sqrt{{{a}^{2}}+{{b}^{2}}}+a}{2} \right)}\),

Subtracting (1) from (3), 2y² = √a² + b² – a → \(y=\sqrt{\left( \frac{\sqrt{{{a}^{2}}+{{b}^{2}}}-a}{2} \right)}\),

∴ √a + ib = ± (x + iy) where \(x=\sqrt{\left( \frac{\sqrt{{{a}^{2}}+{{b}^{2}}}+a}{2} \right)},\,y=\sqrt{\left( \frac{\sqrt{{{a}^{2}}+{{b}^{2}}}-a}{2} \right)}\).

**Example 1: **Find the square root of 3 + 4i.

**Solution: **√3 + 4i \(=\pm \left[ \frac{\sqrt{\sqrt{{{3}^{2}}+{{4}^{2}}}+3}}{2}+i\frac{\sqrt{\sqrt{{{3}^{2}}+{{4}^{2}}}-3}}{2} \right]=\pm \left( 2+i \right)\).

**Example 2: **Find the square root of 7 + 24i.

**Solution:** Let √7 + 24i = ±(x + iy)

If 7 + 24i = a + ib then a = 7, b = 24

\(x=\frac{\sqrt{\sqrt{{{a}^{2}}+{{b}^{2}}}+a}}{2}=\frac{\sqrt{\sqrt{{{7}^{2}}+{{24}^{2}}}+7}}{2}=\sqrt{\frac{32}{3}}=4\),

\(y=\sqrt{\frac{\sqrt{{{a}^{2}}+{{b}^{2}}}-a}{2}}=\frac{\sqrt{\sqrt{{{7}^{2}}+{{24}^{2}}}-7}}{2}=\sqrt{\frac{18}{2}}=3\),

∴ √7 + 24i = ±(4 + 3i).

**Example 3: **Find the square root of – 8 – 6i.

**Solution:** Let √-8-6i = ± (x + iy)

If -8-6i = a + ib then a = -8, b = -6

\(x=\frac{\sqrt{\sqrt{{{a}^{2}}+{{b}^{2}}}+a}}{2}=\frac{\sqrt{\sqrt{64+36}-8}}{2}=\sqrt{\frac{10-8}{2}}=1\),

\(y=\sqrt{\frac{\sqrt{{{a}^{2}}+{{b}^{2}}}-a}{2}}=\frac{\sqrt{\sqrt{64+36}+8}}{2}=\sqrt{\frac{10+8}{2}}=\sqrt{9}=3\),

∴ √-8-6i = ± (1 + 3i).

]]>Angular displacement is the angle in radians through which a point or line has been rotated in a specified sense about a specified axis. It is the angle of the movement of a body in a circular path. It is the difference between the initial and final angular position of a moving body. It has both magnitude and direction.

Conventionally, clockwise movements are described as positive and anticlockwise movements as negative. Also, angular displacement of human body segments usually indicate the type of joint movement.

**What is Angular Displacement?**

Angular Displacement is the angle made by a body while moving in a circular path. When a rigid body is rotating about its own axis, motion ceases to become a particle. It is so because in a circular path velocity and acceleration can change at any time. The rotation of rigid bodies which will remain constant throughout the duration of rotation, over a fixed axis is called rotational motion.

The angle made by the body from its point of rest at any point in the rotational motion is called as Angular Displacement.

**Measurement of Angular Displacement: **Angular Displacement is measured in radians rather than degrees, because it provides a relationship between distance travelled around the circle and the distance from the centre.

It can be measured by using formula:

θ = s/ r

Where,

θ = Angular Displacement,

s = Distance travelled by the body,

r = Radius of the circle.

The displacement of object is the distance travelled by it around the circumference of a circle divided by its radius.

]]>Schedule for Original Certificate Verification for BAMS/ BHMS/ BNYS/ BUMS at JNTU, Kukatpally, Hyderabad.

CENTRE FOR CERTIFICATE VERIFICATION – CANDIDATES RANK WISE DISTRIBUTION

Date | Time | Rank in provisional merit list | Category |

18-09-2018 | 8.30 A.M | 1 to 200 | All Candidates, who fulfilled eligibility conditions belonging to Telangana State and State of Andhra Pradesh are directed to attend for verification with all original certificates. |

12.00 Noon | 201 to 400 | ||

3.00 P.M | 401 to 600 | ||

19-09-2018 | 8.30 A.M | 601 to 800 | |

12.00 Noon | 801 to1000 | ||

3.00 P.M | 1001 to 1200 | ||

20-09-2018 | 8.30 A.M | 1201 to 1400 | |

12.00 Noon | 1401 to 1600 | ||

3.00 P.M | 1601 to 1800 | ||

21-09-2018 | 8.30 A.M | 1801 to 2000 | |

12.00 Noon | 2001 to 2200 | ||

3.00 P.M | 2201 to Last Rank |

**Note:** The eligible candidates are advised to attend for verification of Original Certificates at the specified Help-line centre as per above schedule, subject to fulfilment of above conditions.

**SPECIAL CATEGORY CANDIDATES CERTIFICATE VERIFICATION (PH/ NCC & CAP) AT, J.N.T.U.H. KUKATIPALLY, HYDERABAD.**

NCC Category | 21.09.2018 | 10.00 AM to 1.00 P.M | All Eligible Candidates from 1 to last rank in Provisional merit list for verification with all original certificates |

CAP (Army) Category | |||

Physically Challenged (PH) Category |

**Note:** Special category seats will be allotted as per Govt. rules in force.

**⇒ **The guidelines of Govt. of India and regulations of Medical Council of India shall be observed in making admissions of differently abled (Physically Handicapped) candidates.

**⇒ **The candidate seeking the benefit of reservation should present him/herself before a Medical Board comprising of at least one Expert/ Specialist from the specialty of Orthopedics and one specialist from Department of Medicine of the rank of Professor constituted by KNR UHS, Warangal.

**⇒ **The Medical Board constituted by the Competent Authority will examine and assess the percentage of disability of differently abled candidates, who have applied seeking admission under PH quota. The report of the Medical Board is final for considering a candidate under PH quota as per rules.

**Eligibility for admission into BAMS/ BHMS/ BNYS courses:**

1 | The candidate should be Indian Nationals or Persons of Indian Origin (PIO)/ Overseas Citizens of India (OCI) Card Holders should satisfy the Local or Non-local status in Andhra Pradesh and Telangana (Residence requirement) as laid down in Andhra Pradesh Education Institutions (Regulations of Admissions) Order, 1974 and the selection will be done as per the procedure laid down in the G.O.P.No.646, dated 10.07.1979 as amended in G.O.Ms.No.42, Higher Education Department, dated 18.05.2009 and G.O.Ms.No.170 HM&FW Dept. |

2 | The candidate should have qualified in NEET UG 2018 and must have applied on-line and should be in the provisional merit list for admission into BAMS/ BHMS/ BNYS/ BUMS Course.
The candidate should have passed Intermediate (10 + 2 pattern) or its equivalent examination with Physics, Chemistry, Botany and Zoology with 50% marks aggregate in the group subjects • BC/ SC/ ST candidates should obtain not less than 40% marks in group subjects. |

3 | The candidate should have completed 17 years of age as on 31-12-2018 for all courses. |

**Eligibility for BUMS Course:**

Admissions to Kamil-E-TIB-Wa-Jarahat course: A candidate seeking admission to main Kamil-E-Tib Wa-Jarahat (Bachelor of Unani Medicine and Surgery – B.U.M.S.) Course must have passed.

a) Intermediate 10+2 or equivalent examination with fifty percent (50%) for OC aggregate marks in the subjects of Physics, Chemistry and Biology and Forty Percent (40%) for SC/ST & BC. The candidate should have passed 10th standard with Urdu or Arabic or Persian language as a subject or clear the test of Urdu in the entrance examination conducted by the University or Board or Registered Society authorized by the Government to conduct such examination (or)

b) The Pre-Tib examination of one year duration.

**Processing Fee:** Candidates have to pay a non-refundable processing fee of Rs.2000/- (Rupees Two thousand only) and Rs.1500/- (Rupees One thousand five hundred only) in case of SC/ST) at the time of certificate verification.

**Certificates to be produced at the time of Counselling**:

The candidates are directed to bring all the original certificates (mentioned below) and two sets of self-attested Xerox copies.

**Note:** CUSTODIAN CERTIFICATES ARE NOT PERMITTED.

1. Hall Ticket of NEET-UG 2018 for BAMS/ BHMS/ BNYS/ BUMS Candidates

2. Rank card of NEET-UG 2018 for BAMS/ BHMS/ BNYS/ BUMS Candidates

3. S.S.C or equivalent examination showing the Date of Birth

4. Memorandum of marks of qualifying examination in Intermediate or Equivalent Examination

5. Transfer certificate

6. Study certificates from 6^{th} Class to Intermediate

7. Candidates who have studied in the institutions outside of Telangana/ Andhra Pradesh have to submit 10 years (years of period to be specified) residence certificate of the candidate or either of the parent issued by MRO/ Tahsildar

8. Candidates claiming eligibility of reservation under Special categories should furnish the required certificate in support of their claim

9. Permanent Caste Certificate (Integrated Community Certificate) claiming reservation under BC/ SC/ ST Categories issued by an Officer prescribed.

10. Self Attested copy of Aadhaar Card of candidate and Father and Ration Card.

11. Undertaking in the form of Affidavit on Rs. 100/- Stamp paper by the Parent and candidates stating that the caste and area mentioned in the certificates are genuine and they will be held responsible for any further consequences as per LAW if any discrepancy noticed (Proforma enclosed).

**Dates for Exercising Web Options:**

Candidates whose names are in the final merit list to be displayed on KNRUHS web-site on 23-09-2018, can exercise web-options from 9.00 A.M. on 24-09-2018 to 5.00 P.M. on 25-09-2018.

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